Here is a small amendment to my previous message.

Although h0 becomes negative x does not so I should have written:

if the absolute value of A exceeds 90 degrees, then h0 and thus x becomes
negative. This is the reason for:
  If A < 90, h = x + h0
  If A > 90, h = x - h0

Geoff

On Thu, 18 Jul 2024 at 11:33, Geoff Thurston <thurs...@hornbeams.com> wrote:

> Hi John,
>
> I have just been studying Jim's book and I have to admit that I was
> initially confused by the diagrams. However, after redrawing them for
> myself, I am convinced by Jim's argument and equations provided that
> azimuth is measured from the southern meridian. Referring to his equations:
>
> tan h0  = cos A / tan ϕ
>
> sin x = cos h0. sin d / sin ϕ
>
>
> From the first equation, we can see that h0 takes the same value for
> positive and negative azimuths which is what we would expect. However, if
> the absolute value of A exceeds 90 degrees, then h0 and thus x become
> negative. This is the reason for:
>   If A < 90, h = x + h0
>   If A > 90, h = x - h0
>
> Best wishes,
>
> Geoff
>
> On Wed, 17 Jul 2024 at 19:11, John Goodman via sundial <
> sundial@uni-koeln.de> wrote:
>
>> Diese Nachricht wurde eingewickelt um DMARC-kompatibel zu sein. Die
>> eigentliche Nachricht steht dadurch in einem Anhang.
>>
>> This message was wrapped to be DMARC compliant. The actual message
>> text is therefore in an attachment.
>>
>>
>> ---------- Forwarded message ----------
>> From: John Goodman <johngood...@mac.com>
>> To: Sundial List <sundial@uni-koeln.de>
>> Cc:
>> Bcc:
>> Date: Wed, 17 Jul 2024 15:11:55 -0400
>> Subject: Re: Azimuth and altitude
>> Thank you for explaining. I can see how sine functions are symmetric
>> around 90 degrees but I still don't see how 90 degrees is an axis of
>> symmetry for measuring azimuth.
>>
>> If South is treated as 0 degrees instead of 180 degrees, then, as you
>> describe it, East could be -90 degrees and West would be +90 degrees. The
>> symmetry around South would then be Az < 0° or > 0° but still not the Az <
>> 90° or > 90° that was specified in Morrison's equations.
>>
>> 1. Calculate the sun's altitude when the declination is zero:  tan h0 =
>> cos A / tan phi
>>
>> 2. Calculate an auxiliary angle x from:  sin x = (cos h0 sin d) / sin phi
>>
>> 3. Calculate sun's altitude, h, for the azimuth and declination from:
>>
>>     If A < 90, h = x + h0
>>     If A > 90, h = x - h0
>>
>> NOTE:
>>
>> h = altitude
>> A = azimuth
>> d = solar declination
>> phi = latitude
>>
>>
>> On Jul 12, 2024, at 4:40 AM, Hervé Guillemet <guillemet.he...@free.fr>
>> wrote:
>>
>> Hi John,
>>
>> If I understand your point, I think that the confusion comes from the
>> fact that for gnomonistthe origin of azimuth is South, and not North like
>>  it is for navigators (salesmen, pilots). In such case East is -90°, West
>>  is +90°, North is +/- 180°.
>> With this origin (South = 0°), there is a symetry in the trigonometric
>> circle : sin (pi - A) = sinA.  As an example sin 120° = sin 60° =
>> 0,866... For the same sine value, you have 2 angles. This is why you need
>>  to determine whether Az is > 90° or < 90°
>>
>> I hope that it answers your point.
>> Best regards Hervé Guillemet
>>
>> ------------------------------
>> *De: *"John Goodman via sundial" <sundial <sundial@uni-koeln.de>
>> @uni-koeln.de <sundial@uni-koeln.de>>
>> *À: *"Sundial List" <sundial <sundial@uni-koeln.de>@uni-koeln.de
>> <sundial@uni-koeln.de>>
>> *Envoyé: *Jeudi 11 Juillet 2024 20:03:10
>> *Objet: *Azimuth and altitude
>>
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