Excerpts from Gregor Hoffleit's message:
> With my limited Ruby knowledge, my quick and dirty fix was:
>
> if entry[:refs]!="" then
> d[:refs]=entry[:refs]
> else
> d[:refs]=(m.refs + m.replytos).uniq.join(" ")
> end
>
> Is this what the above code is about?
I would expect it to be something alike. Rails has Object#empty?
which is true (I think) for nil, false, empty list and empty string.
I'd go with
entry[:refs].to_s != ""
to handle nil as "no refs" too.
--
Tero Tilus ## 050 3635 235 ## http://tero.tilus.net/
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