Hi
I'm getting the following error when trying to run supervisor via `sudo` on
OS X Lion using Python 2.7.3:
Traceback (most recent call last):
File "/usr/local/bin/supervisord", line 9, in <module>
load_entry_point('supervisor==3.0a12', 'console_scripts',
'supervisord')()
File
"/usr/local/pythonbrew/pythons/Python-2.7.3/lib/python2.7/site-packages/supervisor/supervisord.py",
line 363, in main
go(options)
File
"/usr/local/pythonbrew/pythons/Python-2.7.3/lib/python2.7/site-packages/supervisor/supervisord.py",
line 373, in go
d.main()
File
"/usr/local/pythonbrew/pythons/Python-2.7.3/lib/python2.7/site-packages/supervisor/supervisord.py",
line 66, in main
setuid_msg = self.options.set_uid()
File
"/usr/local/pythonbrew/pythons/Python-2.7.3/lib/python2.7/site-packages/supervisor/options.py",
line 1116, in set_uid
msg = self.dropPrivileges(self.uid)
File
"/usr/local/pythonbrew/pythons/Python-2.7.3/lib/python2.7/site-packages/supervisor/options.py",
line 1145, in dropPrivileges
os.setgroups(groups)
ValueError: too many groups
This is when running the command:
sudo /usr/local/bin/supervisord -n -c /usr/local/etc/supervisord.conf
It runs fine without sudo, as the currently logged-in user, but
unfortunately I can't run it as this - I need supervisord to start via
launchctl.
Advice?
--
Phillip B Oldham
[email protected]
+44 (0) 7525 01 09 01
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