I was trying to do one of those back of envelope calculations but the 
numbers I came up with are depressingly low. IIRC the formula for power 
in watts is (Kg*m^2*s^-3) So for a sample calculation I considered the 
following;  25mm of rain will fill my cistern which consists of 8, 50 
gallon drums or roughly 1600 liters of water.  If I had placed the 
cistern on stilts (strong ones) at roof level (roughly 10 m) I would 
have 1600 Kg at 10 m head.  If I released all this water and it went 
through a 100 % efficient turbine in 10 seconds I could generate 160 
watts during that time according to the above formula.  Did I do 
something really dumb here or is that realistic?

I feel like I missed something....I hope.

Joe

Evergreen Solutions wrote:

>
>
> 7. In high school I had visions of a device for recharging batteries 
> that went something like this: captures rain in a funnelled system 
> (big opening = more rain), rain travels downhill turning a series of 
> wheels/cogs that via a system of gears works down to a very tight 
> ratio (one spin of the first wheel = ~10 of the smalll wheel) which 
> spin alternators to generate a charge to the batteries. The higher the 
> system starts aerially, the more primary wheels, the more kinetic 
> energy. Never built it, but...seemed reasonable. Then you could use 
> your captured rainwater for your crops/drinking/whatever.
>
>  
>


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