On 01/24/14 16:11, Adrian Chadd wrote:
... How's that matter?
Adrian
Ok, read slowly:
uint32_t x = 255U;
uint8_t y;
On Big endian:
memcpy(&y, &x, 1);
y == 0;
On Little endian:
memcpy(&y, &x, 1);
y == 255;
If I'm not mistaken. The code is wrong because result depends on
endianness :-)
--HPS
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