Change "paramType" to "in" for starters. I suggest checking syntax with
http://editor.swagger.io
> On Aug 8, 2016, at 9:54 AM, Benjamin SOULAS <benjamin.soula...@gmail.com>
> wrote:
>
> Hello people, I am trying to generate my own REST server in python Flask
> framework, actually I only have a GET method and a POST one.
>
> But the POST method IS the problem about paramters which seems not to
> correspond to the YAML Syntax in Swagger. The idea, I need the template ID
> which is into the path and a config in a JSON parameter (is it in body?
> query? Maybe this is it the problem?).
>
> Here is my .YAML file:
>
> # Example YAML to get you started quickly.
> # Be aware that YAML has indentation based scoping.
> # Code completion support is available so start typing for available options.
> swagger: '2.0'
>
> # This is your document metadata
> info:
> version: "0.0.0"
> title: <jitter api>
>
> # Describe your paths here
> paths:
> /v0/templates:
> get:
> description:
> Get the templates list
> produces:
> - application/json
> responses:
> "200":
> description: Successful response
> schema:
> title: ArrayOfTemplates
> type: array
> items:
> type: object
> properties:
> templateId:
> type: string
> description:
> type: string
> /v0/application/new/{templateId}:
> post:
> description: |
> Get the templates list
> consumes:
> - application/json
> produces:
> - application/json
> parameters:
> - name: templateId
> description: Template's Id
> required: true
> type: string
> paramType: path
> - name: config
> description: Config in which we will define the encoder's number do
> deploy
> required: true
> paramType: query
> type: object
> properties:
> encoders_count:
> type: integer
> format: int32
> responses:
> "200":
> description: Successful response
> schema:
> title: object of the app infos
> type: object
> items:
> type: object
> properties:
> appId:
> type: string
> templateId:
> type: string
> config:
> type: object
> properties:
> encoders_count:
> type: integer
> format: int32
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