I just started with swagger code gen Generated client code in python ... in generated sample i have following .......
Request user authorised: userName and cmkey will transfered via header ### Example ```python from __future__ import print_statement import time import swagger_client from swagger_client.rest import ApiException from pprint import pprint # create an instance of the API class api_instance = swagger_client.SecurityApi() cmkey = 'cmkey_example' # str | Session Token try: # Request user authorised: userName and cmkey will transfered via header api_response = api_instance.security_request_user_authorised(cmkey) pprint(api_response) except ApiException as e: print("Exception when calling SecurityApi->security_request_user_authorised: %s\n" % e) ``` ### Parameters Name | Type | Description | Notes ------------- | ------------- | ------------- | ------------- **cmkey** | **str**| Session Token | it accept only one param = cmkey. still says ' userName and cmkey will transfered via header' in actual api need 2 parameters. How do I send both params as one? tried creating python dictionary but only accepts string.... -- You received this message because you are subscribed to the Google Groups "Swagger" group. To unsubscribe from this group and stop receiving emails from it, send an email to swagger-swaggersocket+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.