Le 27 déc. 2015 à 19:54, Wallacy via swift-evolution <swift-evolution@swift.org> a écrit : > Even with backticks would not be possible. > > You may need to reference the method signature altogether. > > var someA = A() > let fn1 = someA.#someFunc(a: Int) -> Int > let fn2 = someA.#someFunc(a: Int) -> Double > let fn3 = someA.#someFunc(a: Double) -> Int > let fn4 = someA.#someFunc(a: Double) -> Double > > An operator at the beginning perhaps? > > let fn1 = #someA.someFunc(a: Int) -> Int > let fn2 = #someA.someFunc(a: Int) -> Double > let fn3 = #someA.someFunc(a: Double) -> Int > let fn4 = #someA.someFunc(a: Double) -> Double
Well, this works today: let fn1: Int -> Int = someA.someFunc let fn2: Int -> Double = someA.someFunc let fn3: Double -> Int = someA.someFunc let fn4: Double -> Double = someA.someFunc In fact, this too works: let fn1: (a: Int) -> Int = someA.someFunc let fn2: (a: Int) -> Double = someA.someFunc let fn3: (a: Double) -> Int = someA.someFunc let fn4: (a: Double) -> Double = someA.someFunc See the parameter name in the type? It could be used to disambiguate, but currently it is not taken into account: if you add a `someFunc` overload taking a different parameter name but the same types the above code becomes ambiguous. -- Michel Fortin https://michelf.ca _______________________________________________ swift-evolution mailing list swift-evolution@swift.org https://lists.swift.org/mailman/listinfo/swift-evolution
