I actually do prefer the explicit variant without type inference as I find it much clearer to see what the typealias requires.
-Thorsten > Am 23.03.2016 um 17:38 schrieb Douglas Gregor via swift-evolution > <swift-evolution@swift.org>: > > Clarification here: the example is > > typealias DictionaryToStrings<T> = Dictionary<T, String> > > Either we infer T to require Hashable, or we call this ill-formed and require > the user to write > > typealias DictionaryToStrings<T: Hashable> = Dictionary<T, String> >
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