So, `Void->Int` functions would work like this? let foo = bar(()) // returns Int
> On Apr 15, 2016, at 3:23 PM, Brent Royal-Gordon via swift-evolution > <swift-evolution@swift.org> wrote: > > What I think we *should* eliminate, however, is using `Void` to mean "no > arguments" in a closure type. `Void -> Int` should mean that the type takes > one argument which happens to be an empty tuple. If you want no arguments, > write `() -> Int`. _______________________________________________ swift-evolution mailing list swift-evolution@swift.org https://lists.swift.org/mailman/listinfo/swift-evolution
