Well no, this proposal won’t allow your example. The problem in your example 
actually has different roots - *Metatypes*. As by today, meta types are somehow 
broken, especially in generic / associated type context. Furthermore there is 
currently no way to express that you may want a subtype for an existential 
metatype instead of the static metatype.

For more informations about meta types and who some of us would like them to 
work, read our proposal here:
https://github.com/DevAndArtist/swift-evolution/blob/refactor_existential_metatypes/proposals/0126-refactor-metatypes.md

Then your example could be expressed as:

```
func register<S>(_ service: Service, ofType type: Type<S>) where AnyType<S> : 
AnyType<Service> {}

// or if I’m not mistaken we can make use if implicit existential like this then
func register<S>(_ service: Service, ofType type: Type<S>) where S : Service {}
```

I don't want to dive any deeper about the metatype pain points, because I don’t 
want to prevent the success of the pitched idea with an off-topic.


Am 25. November 2017 um 16:34:58, Dennis Weissmann (den...@dennisweissmann.me) 
schrieb:

I would also love to have generic associated types in the language, I have a 
lot of uses for them and, IIUC, supertype constraint would enable me to express 
the following:

protocol Service {}

protocol WikiService: Service {} // methods not shown for conciseness
class DefaultWikiService: WikiService {}
class DemoWikiService: WikiService {}

class DataServiceManager {

    private var registry = [String: Service]()

    func register<S>(_ service: Service, ofType type: S.Type) where S: Service {
        let key = "\(Swift.type(of: type))"
        registry[key] = service
    }

    func service<S>(ofType type: S.Type) -> S where S: Service {
        let key = "\(Swift.type(of: type))"

        // It is a programmer error to expect a value for a not yet registered 
type
        guard let service = registry[key] as? S else {
            fatalError("Service of type \(type) cannot be found. Please 
register a service for that type before accessing it.")
        }
        return service
    }

}

let manager = DataServiceManager()
if isDemoMode {
    manager.register(DemoWikiService(), ofType: WikiService.self) // Currently: 
error: in argument type 'WikiService.Protocol', 'WikiService' does not conform 
to expected type 'Service'
} else {
    manager.register(DefaultWikiService(), ofType: WikiService.self) // 
Currently: error: in argument type 'WikiService.Protocol', 'WikiService' does 
not conform to expected type 'Service'
}

If that's right, I'm also +1 on this :)

- Dennis

On Nov 25, 2017, at 12:13 AM, Adrian Zubarev via swift-evolution 
<swift-evolution@swift.org> wrote:

In general this is more then welcome, so +1 for me.

However I have one question:

Could this allow support, or at least be a first step towards Swift allowing 
the following behaviour?

```
extension MyProtocol where Self : SomeClass {
static func getSubtypes<T>(ofType _: T.Type = T.self) -> [T] where T : Self { 
... }
}
```

I would like to be able to upgrade `Self` to a class constraint, which then 
will allow me to only accept subtypes from T at compile time.

Am 25. November 2017 um 00:03:23, Matthew Johnson via swift-evolution 
(swift-evolution@swift.org) schrieb:

One of the most frequent frustrations I encounter when writing generic code in 
Swift is the requirement that supertype constraints be concrete.  When I 
mentioned this on Twitter 
(https://twitter.com/anandabits/status/929958479598534656) Doug Gregor 
mentioned that this feature is smaller and mostly straightforward to design and 
implement (https://twitter.com/dgregor79/status/929975472779288576).

I currently have a PR open to add the high-level description of this feature 
found below to the generics manifesto 
(https://github.com/apple/swift/pull/13012):

Currently, supertype constraints may only be specified using a concrete class 
or protocol type.  This prevents us from abstracting over the supertype.

```swift
protocol P {
  associatedtype Base
  associatedtype Derived: Base
}
```

In the above example `Base` may be any type.  `Derived` may be the same as 
`Base` or may be _any_ subtype of `Base`.  All subtype relationships supported 
by Swift should be supported in this context including, but not limited to, 
classes and subclasses, existentials and conforming concrete types or refining 
existentials, `T?` and  `T`, `((Base) -> Void)` and `((Derived) -> Void)`, etc.

Generalized supertype constraints would be accepted in all syntactic locations 
where generic constraints are accepted.

I would like to see generalized supertype constraints make it into Swift 5 if 
possible.  I am not an implementer so I will not be able to bring a proposal 
forward alone but am interested in collaborating with anyone interested in 
working on implementation.

I am also interested in hearing general feedback on this feature from the 
community at large.  Have you also found this limitation frustrating?  In what 
contexts?  Does anyone have reservations about introducing this capability?  If 
so, what are they?

Matthew

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