i686 is a 32-bit system, right? We don’t support Intel 32-bit on Linux (yet?). 
The only Intel Linux target is x86_64.


> On 10 Jun 2016, at 20:18, Jeff Ramsey via swift-users <swift-users@swift.org> 
> wrote:
> 
> Here you go Dmitri.  It's an older Dell 1501 that was given to me; I wiped it 
> and put Ubuntu on it.  Thanks.
> 
> Python 2.7.6 (default, Jun 22 2015, 18:00:18) 
> [GCC 4.8.2] on linux2
> Type "help", "copyright", "credits" or "license" for more information.
> >>> import platform
> >>> print(platform.system())
> Linux
> >>> print(platform.machine())
> i686
> >>> 
> 
> Here's some additional information if it's useful:
> 
> ~/swift$ lsb_release -a
> No LSB modules are available.
> Distributor ID:    Ubuntu
> Description:    Ubuntu 14.04.3 LTS
> Release:    14.04
> Codename:    trusty
> 
> ~/swift$ uname -a
> Linux Inspiron-1501 3.13.0-74-generic #118-Ubuntu SMP Thu Dec 17 22:52:02 UTC 
> 2015 i686 athlon i686 GNU/Linux
> 
> 
> 
> On Fri, Jun 10, 2016 at 12:31 PM, Dmitri Gribenko <griboz...@gmail.com 
> <mailto:griboz...@gmail.com>> wrote:
> On Fri, Jun 10, 2016 at 9:14 AM, Jeff Ramsey via swift-users
> <swift-users@swift.org <mailto:swift-users@swift.org>> wrote:
> > I followed directions here to clone the compiler source and build it on
> > Ubuntu 14.04:
> >
> > https://github.com/apple/swift/blob/master/README.md 
> > <https://github.com/apple/swift/blob/master/README.md>
> 
> Hi Jeff,
> 
> Which architecture are you running on?
> 
> Could you run "python" in the terminal, type the following script, and
> send me the output?
> 
> import platform
> print(platform.system())
> print(platform.machine())
> 
> Dmitri
> 
> --
> main(i,j){for(i=2;;i++){for(j=2;j<i;j++){if(!(i%j)){j=0;break;}}if
> (j){printf("%d\n",i);}}} /*Dmitri Gribenko <griboz...@gmail.com 
> <mailto:griboz...@gmail.com>>*/
> 
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