> On Nov 14, 2016, at 16:05, Toni Suter via swift-users <swift-users@swift.org>
> wrote:
>
> Hi,
>
> I would have expected that the following code reports an error, because
> of ambiguous function overloads:
>
> infix operator ***: MultiplicationPrecedence
> infix operator +++: AdditionPrecedence
>
> func ***(x: Int, y: Int) -> String {
> print("f1")
> return ""
> }
>
> func ***(x: Int, y: Int) -> Int {
> print("f2")
> return 0
> }
>
> func +++(x: String, y: Int) -> Int {
> print("f3")
> return 0
> }
>
> func +++(x: Int, y: Int) -> Int {
> print("f4")
> return 0
> }
>
> let result = 0 *** 4 +++ 0 // prints f2 and f4
>
>
> As far as I can tell, there are two possible overload resolutions: f1 + f3 or
> f2 + f4.
> I thought that these two solutions get an "equivalent score" and therefore
> there would
> be a compile error. However, that's not the case. Instead, the type checker
> picks
> f2 and f4.
>
> So, I guess my question is, whether there is some rule, that prefers
> operators, which have the same argument types and the same return type
> or whether this is simply a bug.
Odd... Perhaps the compiler is convinced the result of the *** operation needs
to be an Int? Dunno why that would be, though.
What happens if you split it up into two statements?
- Dave Sweeris
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