On 28/12/2016 19:57, Travis Griggs via swift-users wrote:
The behavior of the following playground snippet surprised me:

var source = [10, 20, 30, 40]
var stream = source.makeIterator()
stream.next()  // 10
stream.next()  // 20
stream.forEach { (each) in
        print("\(each)")
}  // prints 30, 40 to the console
stream.next()  // 30
stream.next()  // 40
stream.next()  // nil

I can move the forEach statement up and down the stack there, and it *appears* 
that while it respects the the current position of the stream/iterator as a 
start point, it does not actually consume the elements (as next does). That 
seems inconsistent to me I guess. I would have expected the forEach to either 
pass through to the source and just ignore the current position, or to consume 
the items. Whereas the current behavior is kind of a hybrid.

Guess I’m just looking for some enlightenment as to why it was designed to work 
this way. I figure there’s some valuable insight here that I’m missing.

The IndexingIterator returned by `source.makeIterator()` is itself a `Sequence` (you couldn't call `forEach` if it weren't).

When you call `forEach` (which is implemented using a `for ... in` loop), you effectively call `stream.makeIterator()`, thus making a new iterator. The state of the original `stream` iterator isn't affected by this.

You can see more clearly what happens when you deconstruct the call to `forEach`, first into a for-in loop and then into a while loop (which is equivalent to the for-in loop). All three variants give the same result even if called sequentially on the same sequence, because a new iterator is created for each loop:

// ...
stream.next()  // 10
stream.next()  // 20
stream.forEach { (each) in
    print("forEach \(each)")
}  // prints 30, 40 to the console

// for-in loop has the same effect
for element in stream {
    print("for in \(element)")
} // prints 30, 40 to the console

// while loop has the same effect
// Here you can see that a new iterator is created.
var iter = stream.makeIterator()
while let element = iter.next() {
    print("while \(element)")
}

stream.next()  // 30
stream.next()  // 40
stream.next()  // nil

(The result would be different if the sequence were _destructively consumed_, i.e. it can only be iterated over once -- which is allowed by the Sequence protocol).

_______________________________________________
swift-users mailing list
swift-users@swift.org
https://lists.swift.org/mailman/listinfo/swift-users

Reply via email to