Why you have to use `unwrapped optional` at the first place? If you have to
use it, it means it could be nil. So it won't conform the protocol, which
requires the `value` never nil.
Zhaoxin
On Mon, May 29, 2017 at 12:37 PM, Anton Bronnikov via swift-users <
swift-users@swift.org> wrote:
> Hi All,
>
> If I have a protocol with a property requirement such as:
>
> protocol Foo {
> var value: Int { get }
> }
>
>
> .. and I need to conform to it using an implicitly unwrapped optional like:
>
> struct Bar : Foo {
> let value: Int! = nil
> }
>
>
> .. then the compiler fails with an error:
>
> *Playground execution failed: error: scratchpad.playground:5:8: error:
> type 'Bar' does not conform to protocol 'Foo'*
> *struct Bar : Foo {*
> * ^*
>
> *scratchpad.playground:2:9: note: protocol requires property 'value' with
> type 'Int'; do you want to add a stub?*
> * var value: Int { get }*
> * ^*
>
> *scratchpad.playground:6:9: note: candidate has non-matching type 'Int!'*
> * let value: Int! = nil*
> * ^*
>
> Technically, I understand why the error, and currently work around it with
> a cumbersome:
>
> struct Bar : Foo {
> var value: Int { return _value! }
> let _value: Int? = nil
> }
>
>
> However, I keep wondering - would it not be making sense to accept
> implicitly unwrapped optionals as a conformance to be base-type
> requirements? It sort of works just like that in all other parts of the
> language.
>
> Or in other words, is this by design, or should I probably create an issue
> for this?
>
> Thank you.
> Cheers,
> Anton
>
> P.S. The example is oversimplified for the sake of clarity, in practice
> the property just has to be an optional - implicitly unwrapped or not -
> because it’s a part of the composite that holds unowning reference to its
> container object.
>
>
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>
>
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