> On Sep 15, 2017, at 12:40 PM, Joanna Carter via swift-users
> <[email protected]> wrote:
>
> Greetings
>
> Now we've got generic subscripts, I thought I'd play…
>
> protocol DataProvider
> {
> subscript<itemType>(index: Int) -> itemType { get }
> }
This is a valid usage of your protocol:
func doesStuff(p: DataProvider) {
let i: Int = p[0]
let s: String = p[1]
}
>
> class Test : DataProvider // error : Type 'Test' does not conform to protocol
> 'DataProvider'
> {
> subscript(index: Int) -> String
> {
> return "Fred"
> }
> }
>
> Simple questions:
>
> 1. why does this not compile?
Imagine if I pass an instance of class Test to my function doesStuff() above.
What would the first line of code do, given that it’s expecting to get back an
Int result but the subscript in the class always returns a String?
> 2. should it?
> 3. is there a workaround without declaring an associated type in the protocol?
Either the protocol should have a non-generic subscript, or the class should
have a generic subscript. Note that the same would happen if you do something
like
protocol P {
func f<T>() -> T
}
class C : P {
func f() -> String
}
Again, here C.f is ‘too concrete’.
Slava
>
> Joanna
>
> --
> Joanna Carter
> Carter Consulting
>
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