Hi I've a question regarding how to design a feature of my project. my project has a question/answer section, a forum section and a tutorial section. I want to add a "flag as inapropriate" functionality to each of the tables (question, answer, forum, forum_comment, recipe, recipe_comment). I want to have a table where i store who flagged which object. if the same object if flagged twice then it's 'is_abuse' field is set to true and the abuser's account is blocked.
now I'we two ideas how to solve this and Im wondering which one you consider better: 1. create a single table with object_type and object_id as attribute [code]AbuseFlags: columns: object_type: type: enum values: [question, answer, forum, forum_comment, recipe, recipe_comment] primary: true notnull: true object_id: type: integer(4) primary: true notnull: true flagger_user_id: type: integer(4) primary: true notnull: true abuser_user_id: type: integer(4) primary: true notnull: true [/code] 2. create a separate table (like a m:n relation) for each object type. [code]ForumCommentsAbuseFlags: columns: forum_comment_id: type: integer(4) primary: true notnull: true flagger_user_id: type: integer(4) primary: true notnull: true abuser_user_id: type: integer(4) primary: true notnull: true [/code] or do you have a better idea, I'm shure this has been done a coupple of times allready! As far as i'm concerned I wouldent mind having some model method taking care of getting the table name of the offending object and set it as object_type in the AbuseFlag table.I was just wondering if from a design (and symfony -my first project with it-) point of view which one made more sense thanks a lot Marco --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "symfony users" group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en -~----------~----~----~----~------~----~------~--~---