I want to validate my object cause these will not be given in by a
form but by URL (cause the frontend requires this)
so actualy i want a modelvalidation but i don't think this is possible
so i tried putting my object in the form and then
validate the form. but it always returns false and i looked at it if
the form is shown it actualy shows the input is written in it
but still the valid doesn't return true (and al validation rules are
ok)
On 20 apr, 08:07, Gareth McCumskey <gmccums...@gmail.com> wrote:
> The isValid() method is a validation check on user input after a user
> has submitted a form based on the validators you create in the forms
> object. Its not used to see if the form structure itself is valid.
>
>
>
>
>
> On Mon, Apr 19, 2010 at 4:37 PM, kim <thechosendra...@gmail.com> wrote:
> > hello,
>
> > To see if a object is correct i put it in a form (but never show it)
> > then i try the isValid() function but this always shows false
> > i tried to check global errors, errors but all arrays are empty
>
> > this is my code:
>
> > $form = new paperForm($paper);
> > $form->disableCSRFProtection();
> > if($form->isValid()){
> > echo 'correct';
> > }else{
> > echo 'incorrect';
> > }
>
> > PaperForm.Class
>
> > public function configure()
> > {
> > $this->validatorSchema['email'] = new sfValidatorAnd(array($this-
> >>validatorSchema['email'], new sfValidatorEmail()));
> > }
>
> > it always shows incorrect. and when i echo $form->isValid(); it just
> > shows nothing
>
> > thanks
> > Greetings
>
> > --
> > If you want to report a vulnerability issue on symfony, please send it to
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> --
> Gareth McCumskeyhttp://garethmccumskey.blogspot.com
> twitter: @garethmcc
>
> --
> If you want to report a vulnerability issue on symfony, please send it to
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