Hi, That should do the trick for me.
I wonder how gmail or facebook do this. On Tue, Jan 18, 2011 at 12:38 PM, Gareth McCumskey <gmccums...@gmail.com>wrote: > The best you can do is try to use javascript to catch an event of the > person leaving the page (http://api.jquery.com/unload/). the problem as > that link suggests is that its also browser dependant. Some browsers > implement only parts of that event. For example, some browsers do not fire > the unload event on browser closing but do on changing url in the tab etc. > Its a very tricky thing to do. > > The best way I can think of is have a periodic ajax request fire every 1 > minute or or so. This ajax event updates the users "last active" time. All > other users IM client can then update the currently online people to be > those whose last active time was updated in the last minute. In other words, > if I am a user who has a list of currently logged in people, and my friend > has his browser open, he sees me online. My browser is regularly sending the > a small ajax request to the server telling it that at time now I am online. > My friends browser checks to see who is online every minute as well. I close > my browser and now my last active time is not being changed. My friends > browser gets the list of people online and sees that my last active time is > now longer than a minute ago therefore I must be offline. > > > On Tue, Jan 18, 2011 at 8:19 AM, Srivatsa Prasad > <srivatsa6...@gmail.com>wrote: > >> Hi, >> >> Thank you for the response. >> >> The scenario u mentioned below, I see one issue, which cannot be handled. >> >> I think of using the database to see who are all the logged in users, i do >> it at the time when they log-in. I can mark them as logged out if they log >> out, >> >> The problems i foresee are, >> 1 The user session doesn't expire since the page makes a request in a >> certain interval. I don't mind if the session doesn't expire. >> 2 The other issue is if the user closes the browser or the user losses >> connectivity, i am not sure how to handle this situation , how to notify >> other users that an other user has logged out ? >> >> If u could give me some idea on the 2nd issue, i will take it further . >> >> >> >> >> >> >> On Mon, Jan 17, 2011 at 5:50 PM, Gareth McCumskey >> <gmccums...@gmail.com>wrote: >> >>> This is very commonly asked and the simple answer is .... its rather >>> difficult. >>> >>> Its difficult because when someone logs into an application, this fact is >>> stored server-side where all the PHP code exists. Lets consider a scenario. >>> You have an application to which people need to log into. Your session >>> timeout (i.e. how long you allow someone to stay logged in with no >>> interaction) is set to 30 minutes. Someone comes along and logs in. When he >>> logs in you can record the exact time he logged in. Everytime this user >>> accesses a page that calls your application you can update that timestamp to >>> confirm him as still online. But then the requests (i.e. clicking of links, >>> form submission, etc) stops, and 30 minutes later the session timesout. >>> >>> The problem? What if he had closed his browser and not clicked the logout >>> link? Was he actually still sitting in front of his computer when his >>> session ended? At what time in those last 30 minutes of inactivity was he >>> still there? When did he close the browser? >>> >>> You don't know. Closing the browser is something you cannot determine, >>> even using javascript. >>> >>> The only way to reliably do this is to have some ajax sitting in the >>> application that sends a request every few minutes that can verify that the >>> person is still there and his browser is still open. The downside is that >>> his session will never timeout on its own (as each little ajax request will >>> reset the internal PHP session timer) and you will have to build your own >>> session timeout mechanism from scratch to force a "logout" when it does >>> timeout. >>> >>> On Mon, Jan 17, 2011 at 1:49 PM, Srivatsa Prasad <srivatsa6...@gmail.com >>> > wrote: >>> >>>> Hi All, >>>> >>>> I am using symfony 1.4 and doctrine. >>>> I am trying to build a small chat app so, >>>> I want to know who are all the user of my app logged into to at now. >>>> >>>> -- >>>> Thanks & Regards >>>> Srivatsa >>>> >>>> -- >>>> If you want to report a vulnerability issue on symfony, please send it >>>> to security at symfony-project.com >>>> >>>> You received this message because you are subscribed to the Google >>>> Groups "symfony users" group. >>>> To post to this group, send email to symfony-users@googlegroups.com >>>> To unsubscribe from this group, send email to >>>> symfony-users+unsubscr...@googlegroups.com<symfony-users%2bunsubscr...@googlegroups.com> >>>> For more options, visit this group at >>>> http://groups.google.com/group/symfony-users?hl=en >>>> >>> >>> >>> >>> -- >>> Gareth McCumskey >>> http://garethmccumskey.blogspot.com >>> twitter: @garethmcc >>> identi.ca: @garethmcc >>> >>> -- >>> If you want to report a vulnerability issue on symfony, please send it to >>> security at symfony-project.com >>> >>> You received this message because you are subscribed to the Google >>> Groups "symfony users" group. >>> To post to this group, send email to symfony-users@googlegroups.com >>> To unsubscribe from this group, send email to >>> symfony-users+unsubscr...@googlegroups.com<symfony-users%2bunsubscr...@googlegroups.com> >>> For more options, visit this group at >>> http://groups.google.com/group/symfony-users?hl=en >>> >> >> >> >> -- >> Thanks & Regards >> Srivatsa >> >> -- >> If you want to report a vulnerability issue on symfony, please send it to >> security at symfony-project.com >> >> You received this message because you are subscribed to the Google >> Groups "symfony users" group. >> To post to this group, send email to symfony-users@googlegroups.com >> To unsubscribe from this group, send email to >> symfony-users+unsubscr...@googlegroups.com<symfony-users%2bunsubscr...@googlegroups.com> >> For more options, visit this group at >> http://groups.google.com/group/symfony-users?hl=en >> > > > > -- > Gareth McCumskey > http://garethmccumskey.blogspot.com > twitter: @garethmcc > identi.ca: @garethmcc > > -- > If you want to report a vulnerability issue on symfony, please send it to > security at symfony-project.com > > You received this message because you are subscribed to the Google > Groups "symfony users" group. > To post to this group, send email to symfony-users@googlegroups.com > To unsubscribe from this group, send email to > symfony-users+unsubscr...@googlegroups.com<symfony-users%2bunsubscr...@googlegroups.com> > For more options, visit this group at > http://groups.google.com/group/symfony-users?hl=en > -- Thanks & Regards Srivatsa -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups "symfony users" group. 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