Comment #4 on issue 1385 by Vinzent.Steinberg: Integral.midpoint()  
implemented
http://code.google.com/p/sympy/issues/detail?id=1385

So n is the number of rectangles approximating the integral? Ok, now I got,  
it's
indeed pretty basic calculus. :)

Personally, I'd prefer middlesum(), because this is imho more accurate (an  
integral
is a sum and not a point). I find midpoint() misleading.

Apart from that: +1


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