Status: New Owner: ---- Labels: Type-Defect Priority-Medium New issue 1561 by tom.denniston: lambdify doesn't seem to work with logic operations http://code.google.com/p/sympy/issues/detail?id=1561
I'm using sympy 0.6.5 I took an example from the docs on the logic module y|x&y and I tried to use the lambdify function on it. It failed saying "Or" was undefined: >>> x,y = sympy.symbols('x y') >>> expr = (y | (x & y) >>> sympy.lambdify(['x','y'],expr, modules = ['numpy'])(1,[0,1]) I can fake it by doing this, but you can see why this would be non-ideal: >>> sympy.lambdify(['x','y','Or','And'],expr, modules = ['numpy'])(1,[0,1], Or = numpy.logical_or, And = numpy.logical_and) array([False, True], dtype=bool) It seems the functionality to construct the namespace doesn't have support for the logic operators. -- You received this message because you are listed in the owner or CC fields of this issue, or because you starred this issue. You may adjust your issue notification preferences at: http://code.google.com/hosting/settings --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sympy-issues" group. To post to this group, send email to sympy-issues@googlegroups.com To unsubscribe from this group, send email to sympy-issues+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sympy-issues?hl=en -~----------~----~----~----~------~----~------~--~---