Updates:
Cc: -ondrej.certik Ronan.Lamy
Comment #3 on issue 1758 by asmeurer: fix curvilinear_coordinates example
output
http://code.google.com/p/sympy/issues/detail?id=1758
In the relativity example:
dsolve(S("diff(lamda(r), r, r)/2 + diff(lamda(r), r)/r - diff(lamda(r),
r)**2/2"), S("lamda(r)"))
# return r"lambda"
nu = Function("nu")
-lam = Function("lamda")
+lam = Function("lambda")
t=Symbol("t")
r=Symbol("r")
@@ -208,9 +208,9 @@ def main():
#print "scalar curvature:"
#print curvature(Rmn)
print "-"*40
- print "solve the Einstein's equations:"
+ print "Solve Einstein's equations:"
e = e.subs(nu(r), -lam(r))
- l = dsolve(e, [lam(r)])
+ l = dsolve(e, lam(r))
pprint( Eq(lam(r), l) )
I think lam should be lamda not lambda, so it pretty prints to a λ. Also,
the line below this should be just "print l", because
dsolve returns an Eq instance already (always). (Is that the weird result
you referenced?) Solve can't solve that equation, so it
will be implicit.
Also, there are other calls to dsolve that aren't used that would fail if
they were because they still use the old syntax.
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