Comment #5 on issue 1905 by abro...@verizon.net: Differentiation and
Geometric Algebra
http://code.google.com/p/sympy/issues/detail?id=1905
I 'A' is a multivector function do not use diff(A,x) since diff is not part
of the GA
module and does not test to see if A is a multivector. Use A.diff(x) since
this is a
member function of the MV class in the GA module.
If A is a multivector such that A*A is a scalar then in general -
exp(A) = sympy.cosh(sympy.sqrt((A*A)()))+sympy.sinh(sympy.sqrt((A*A)()))*A
However sympy (this has nothing to do with the geometric algebra module)
could have
problems simplifying sympy.sqrt((A*A)()).
If you know that A = f(x)*W where f(x) is a sympy function and W is a
multivector
that can be normalized so that W*W = +/- 1 then use for W*W = 1
exp(f(x)*W) = cosh(f(x))+sinh(f(x))*W
or for W*W = -1
exp(f(x)*W) = cos(f(x))+sin(f(x))*W
If you want more help show what A is for you case.
P.S.: It would be easier to do this through email (abro...@verzion.net)
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