Comment #75 on issue 1694 by nicolas.pourcelot: solve has many issues with
fractions
http://code.google.com/p/sympy/issues/detail?id=1694
"Are you accessing the branch, Nicolas, or did you prefer a patch?"
It cost me a few tries, but I found the command. :)
git clone -b nic http://github.com/smichr/sympy.git
You said 4) was done however, but I didn't see it: simplification still
occurs in solve() instead of _solve_one_equation().
(This is important if strategy == GS_POLY for example, since we set
flags['simplified'] = flags.get('simplified', False).
If the simplification doesn't occur in _solve_one_equation(), flags change
will be lost).
A few new comments also:
5) If you move solution simplification in _solve_one_equation(), you can
remove it here:
if len(symbols) != 1:
result = {}
for s in symbols:
result[s] = _solve_one_equation(f, s, **flags)
if flags.get('simplified', True):
for s, r in result.items():
result[s] = map(simplify, r)
return result
will become:
if len(symbols) != 1:
result = {}
for s in symbols:
result[s] = _solve_one_equation(f, s, **flags)
return result
6) I didn't notice first, but there is some drawback to use the same flag
('simplified') for checkout() and solve().
If simplified=True, checkout() will not simplify solution, so solution
simplification should always happen *before* calling checkout().
(This will only happen with this particular combination of flags:
numerical_check=False and simplified=True)
7) Maybe you should put a short comment here, to explain that num/denom
decomposition only occurs on first path ?
if flags.get('_solve_one_first', True):
flags['_solve_one_first'] = False
f, d = f.as_numer_denom()
else:
d = S.One
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