Comment #4 on issue 1818 by smichr: coeff and collect failures on x**(1+x)
http://code.google.com/p/sympy/issues/detail?id=1818
regarding comment 1: the 2-arg mul behavior gets you here since the 3 gets
distributed into the Add so there is no 1 + x term. You would have to
factor the expression to get it in this form
h[5] >>> (3*(1+x)*x**2)
x**2*(3 + 3*x)
You can, however get the coefficient of 3*(1+x) or of 1 + x if 3 is
replaced with y:
h[7] >>> (3*(1+x)*x**2).coeff(3*(1+x))
x**2
h[8] >>> (y*(1+x)*x**2).coeff(1+x)
y*x**2
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