Comment #14 on issue 2607 by asmeurer: as_numer_denom() is too slow
http://code.google.com/p/sympy/issues/detail?id=2607
Another way would be to not distribute the denominator in each step, so
compute
(a1*d2 + a2*d1)/(d1*d2)
((a1*d2 + a2*d1)*d3 + a3*d1*d2)/(d1*d2*d3)
(((a1*d2 + a2*d1)*d3 + a3*d1*d2)*d4 + a4*d1*d2*d3/(d1*d2*d3*d4)
This is super fast for the expression I gave above where the denominators
are all just 1, but it's slow for actual expressions.
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