Comment #7 on issue 3189 by pr...@goodok.ru: Calculate eigenvectors numericly if it impossible calculate symbolical
http://code.google.com/p/sympy/issues/detail?id=3189
But if "a" is real, then: In [39]: a = Symbol('a', real=True) In [40]: vals = roots(x**2 - (1 + a)*x + a, x) In [41]: v1 = vals.keys()[0] In [42]: v2 = vals.keys()[1] In [43]: v1 Out[43]: a │a - 1│ 1 ─ - ─────── + ─ 2 2 2 In [44]: v1.expand(complex=True) Out[44]: a │a - 1│ 1 ─ - ─────── + ─ 2 2 2 In [45]: v2 Out[45]: a │a - 1│ 1 ─ + ─────── + ─ 2 2 2 About this example we can think how to deal with this sets of roots If a > 1 the the list of roots is: (1/2, a + 1/2), otherwise (a+1/2, 1/2). -- You received this message because you are subscribed to the Google Groups "sympy-issues" group. To post to this group, send email to sympy-issues@googlegroups.com. To unsubscribe from this group, send email to sympy-issues+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sympy-issues?hl=en.