Updates:
Status: Valid
Comment #1 on issue 3692 by asmeu...@gmail.com:
(Symbol("n",integer=True,even=True)/2).is_integer = False !
http://code.google.com/p/sympy/issues/detail?id=3692
But note that the new assumptions get it right
In [60]: ask(Q.integer(n/2), Q.even(n))
Out[60]: True
In [61]: ask(Q.integer(n/2), Q.odd(n))
Out[61]: False
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