Comment #2 on issue 3721 by smi...@gmail.com: solve should handle more than
one abs
http://code.google.com/p/sympy/issues/detail?id=3721
yes...here is a better example
eq = abs((2*x+5))-3*abs((2*x-2))
It may be as simple as replacing abs with sqrt(arg**2):
eq.replace(Abs, lambda x: sqrt(x**2))
-3*sqrt((2*x - 2)**2) + sqrt((2*x + 5)**2)
solve(_)
[1/8, 11/4]
[eq.subs(x,i) for i in _]
[0, 0]
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