Comment #2 on issue 3837 by smi...@gmail.com: RootOf.free_symbols gives wrong result
http://code.google.com/p/sympy/issues/detail?id=3837

The roots routine gives RootOf a symbol to use (apparently) and RootOf reports non-dummies as free symbols

sol[0]
RootOf(x**3 + 4*x + 1, 0)
_.free_symbols
set([x])
sol[0].subs(x,Dummy()).free_symbols
set([])



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