Comment #34 on issue 3128 by someb...@bluewin.ch: Sum and Product
manipulations
http://code.google.com/p/sympy/issues/detail?id=3128
If you want to compute the number of all the "x" in your graph, then
we can easily make sure that the left boundary of that double triangle
is always smaller or equal to the right one by using "Abs":
a = k - 2
b = 2 - k
Sk = Sum(1, (x, -Abs(a), Abs(b))).doit()
Sk
Abs(-k + 2) + Abs(k - 2) + 1
M = Sum(Sk, (k, 0, 4)).doit()
M
17
which is correct.
This is similar on how to use integration to compute the area below a curve.
integrate(sin(x), (x, 0, 2*pi))
0
which is of course "wrong" or rather not what we asked for because the area
carries a sign. The error is not in the math or implementation but simply
comes from an unsuitable problem statement.
Indeed, if we pose the correct question, we get the "right" answer:
Abs(integrate(sin(x), (x, 0, pi))) + Abs(integrate(sin(x), (x, pi,
2*pi)))
4
Note that I split the integral at x=pi because Sympy does a bad job on
integrate(Abs(sin(x)), (x, 0, 2*pi)).
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