Comment #6 on issue 1637 by jan.poes...@gmail.com: solve([Eq(x+a*y,1),
Eq(x+y+z, 1), Eq(z+3*x)], x, y, z, a) troubles
http://code.google.com/p/sympy/issues/detail?id=1637
While this works as expected:
In [1]: solve(x**2-1,[x,y])
Out[1]: {x: [1, -1], y: []}
Giving the equation in a list produces an error:
In [2]: solve([x**2-1],[x,y])
---------------------------------------------------------------------------
PolynomialError Traceback (most recent call last)
/Users/Jan/<ipython console> in <module>()
/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/sympy/solvers/solvers.pyc
in
solve(f, *symbols, **flags)
383 soln = solve_linear_system(matrix, *symbols,
**flags)
384 else:
--> 385 soln = solve_poly_system(polys)
386
387 # Use swap_dict to ensure we return the same type as
what was
/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/sympy/solvers/polysys.pyc
in
solve_poly_system(system, *symbols)
112 head, tail = f.unify_with(system)
113
--> 114 solutions = solve_reduced_system([head] + tail, True)
115
116 if solutions is None:
/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/sympy/solvers/polysys.pyc
in
solve_reduced_system(system, entry)
69 f = univariate.pop()
70 else:
---> 71 raise PolynomialError("Not a zero-dimensional system")
72
73 zeros = roots(Poly(f, f.symbols[-1])).keys()
PolynomialError: Not a zero-dimensional system
I think this should be handled consistently.
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