Ondrej Certik wrote: > On Tue, Oct 7, 2008 at 12:07 AM, Alan Bromborsky <[EMAIL PROTECTED]> wrote: > >> Ondrej Certik wrote: >> >>> On Mon, Oct 6, 2008 at 11:28 PM, Alan Bromborsky <[EMAIL PROTECTED]> wrote: >>> >>> >>>> Suppose I have two symbols A and B that I wish to declare implicit >>>> functions of say the symbols x1, x2, and x3. Then I wish to calculate >>>> the derivative of A*B with respect to x1 and x2 and x3. Can I do this >>>> and if so how? >>>> >>>> >>> Yes, for example this way: >>> >>> In [2]: A = Function("A") >>> >>> In [3]: B = Function("B") >>> >>> In [4]: var("x1 x2 x3") >>> Out[4]: (x₁, x₂, x₃) >>> >>> In [5]: f = A(x1, x2, x3)*B(x1, x2, x3) >>> >>> In [6]: f >>> Out[6]: A(x₁, x₂, x₃)⋅B(x₁, x₂, x₃) >>> >>> In [7]: diff(f, x1) >>> Out[7]: >>> d d >>> A(x₁, x₂, x₃)⋅───(B(x₁, x₂, x₃)) + B(x₁, x₂, x₃)⋅───(A(x₁, x₂, x₃)) >>> dx₁ dx₁ >>> >>> >>> >>> >>> Ondrej >>> >>> >> Is there anyway of suppressing the arguments so you could write f = A*B >> and then d(A*B)/dx1 = dA/dx1*B+A*dB/dx1. I guess what I am saying is >> that writing A(x1,x2,x3) could get very long especially if the A's and >> B's are components of vectors or matrices and you are differentiating >> all of them. It would be very useful to declare the independent >> variables when you declare A as a function so you do not have to write >> out A(x1,x2,x3) every time you use A in an expression or differentiate it. >> > > Like below? > > In [1]: var("x1 x2 x3") > Out[1]: (x₁, x₂, x₃) > > In [2]: A = Function("A")(x1, x2, x3) > > In [3]: B = Function("B")(x1, x2, x3) > > In [4]: f = A*B > > In [5]: diff(f, x1) > Out[5]: > d d > A(x₁, x₂, x₃)⋅───(B(x₁, x₂, x₃)) + B(x₁, x₂, x₃)⋅───(A(x₁, x₂, x₃)) > dx₁ dx₁ > > > > Ondrej > > > > Yes almost, but can you suppress the (x1,x2,x3) in the output so that the output would be
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