Hello, the following code only gives [1] but I would also have the multilplicity of the root 1 (which is 3) : =============== x = sympy.Symbol('x') f = '(x-1)**3' sympy.solve(f, x) ===============
Is there a way to know that ? Christophe. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sympy" group. To post to this group, send email to sympy@googlegroups.com To unsubscribe from this group, send email to sympy+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sympy?hl=en -~----------~----~----~----~------~----~------~--~---