On Aug 2, 12:14 am, smichr <smi...@gmail.com> wrote: > >>> num,den = (1/(.001+a)**3-6/(.9-a)**3).as_numer_denom() > >>> nsolve(num,a,.3) # no need for sympy now
Maybe solve()/nsolve() should do this for you. What do you think? Vinzent --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sympy" group. To post to this group, send email to sympy@googlegroups.com To unsubscribe from this group, send email to sympy+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sympy?hl=en -~----------~----~----~----~------~----~------~--~---
