I think Poly.cancel(expr) is what you want.
Aaron Meurer
Sent from my iPod touch.
On Mar 11, 2010, at 9:56 AM, dschult <dsch...@colgate.edu> wrote:
I'm enjoying exploring this package. Thank you!
I have a question about the "best" way or "standard practice" for
helping sympy simplify expressions.
My output from solving a linear system looks like a quotient with many
terms in the top that multiply
the denominator and thus could be simplified. I'd like to be able to
simplify those terms.
Here's a simple example:
from symp.abc import *
div=1/(a+b)
expr=(a+a*r+b*r)*div
print expr
(a+a*r+b*r)/(a+b)
I'd like to present this as: a/(a+b) + r or similar
Here's my solution:
bplusa=sympy.Symbol('bplusa')
tmp=sympy.expand(expr.subs(b,bplusa-a))
print tmp
r + a/bplusa
print tmp.subs(bplusa,b+a)
r + a/(a+b)
Is this a reasonable approach? Do others have a better way to do
this--especially one that doesn't rely on knowledge of what the
denominator is so it can be automated?
Thanks,
Dan
--
You received this message because you are subscribed to the Google
Groups "sympy" group.
To post to this group, send email to sy...@googlegroups.com.
To unsubscribe from this group, send email to sympy+unsubscr...@googlegroups.com
.
For more options, visit this group at http://groups.google.com/group/sympy?hl=en
.
--
You received this message because you are subscribed to the Google Groups
"sympy" group.
To post to this group, send email to sy...@googlegroups.com.
To unsubscribe from this group, send email to
sympy+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/sympy?hl=en.
