Hi, > The problem is that, if I pass a dictionary, and a module, as a > namespace, to sympy lambdify, then I can apparently overwrite the > namespace of a function that has already been instantiated. I > realize that's not very clear, but I hope this script helps to > explain: > > n1 = {'f': lambda x:'first f', > 'g': lambda x:'first g'} > n2 = {'f': lambda x:'second f', > 'g': lambda x:'second g'} > > f = sympy.Function('f') > g = sympy.Function('g') > x = sympy.Symbol('x') > > if1 = sympy.lambdify(x, f(x), modules=(n1, "sympy")) > print 'f(x) before dict, string;', if1(1) > if2 = sympy.lambdify(x, g(x), modules=(n2, "sympy")) > print 'f(x) after dict, string;', if1(1) > > - gives this output: > > f(x) before dict, string; first f > f(x) after dict, string; second f
In case anyone ends up following this thread, I posted a bugfix for this on sympy-patches. I hope: http://groups.google.com/group/sympy-patches/browse_thread/thread/cf2f122b3d36d7f0# Cheers, Matthew -- You received this message because you are subscribed to the Google Groups "sympy" group. To post to this group, send email to sy...@googlegroups.com. To unsubscribe from this group, send email to sympy+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.