I don't think it's possible to substitute just theta without concern for x, but
this should work
In [9]: f = Function('theta')(x)
In [10]: f
Out[10]: θ(x)
In [11]: expr = 6*f + x
In [12]: expr
Out[12]: x + 6⋅θ(x)
In [13]: g = Function('beta')(x)
In [14]: g
Out[14]: β(x)
In [15]: expr.subs(f, g)
Out[15]: x + 6⋅β(x)
Aaron Meurer
On Sep 7, 2010, at 6:31 AM, Rahul Siddharthan wrote:
> Question that I couldn't see answered in the docs, sorry if it's dumb.
>
> Suppose I define
> f = Function("theta")(x)
> [output] => theta(x)
>
> Then, later on, I want to substitute theta in f with an actual
> function (or alternatively, substitute theta(x) with a number). Is
> this possible? I couldn't see how to do this with f.subs().
>
> Thanks,
>
> Rahul
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