But that only groups together one variety of M**(n+1). If you want
them all together you have to give them a common coefficient that can
be used for collection:
>>> u = Dummy('u')
These are the quantities that may have the n+1 power
>>> expr2.atoms(IndexedElement)
set([M(1, 2), M(1, 1), M(2, 1)])
So we replace them with u*M**(n+1) and colelct on u
>>> collect(expr2.subs([(a**(n+1), u*a**(n+1)) for a in _]), u)
_u*(B*M(2, 1)**(1 + n) - D*M(1, 1)**(1 + n) - E*M(2, 1)**(1 + n)) +
A*M(1, 1)**n - C*M(1, 2)**n
Then split the expression into u-independent and u-dependent pieces
with as_independent and feed that back to Eq with the *prefix and
remove the u by replacing with 1.
>>> Eq(*_.as_independent(u)).subs(u, 1)
A*M(1, 1)**n - C*M(1, 2)**n == B*M(2, 1)**(1 + n) - D*M(1, 1)**(1 + n)
- E*M(2, 1)**(1 + n)
All the n+1 powers are on the right now.
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