ma., 20.09.2010 kl. 22.06 -0600, skrev Aaron S. Meurer: > Yeah, see one of my previous emails on this thread. I was doing something > stupid, and so it didn't work when I tried it. The problem now is with > > >>> m.args[-1] == n > False >
A workaround is to use : >>> m.args[-1] == Idx(n) True There is actually also a test for this behaviour. But it was a horrible design decision, hence issue 2059. Øyvind > Aaron Meurer > > On Sep 20, 2010, at 10:04 PM, smichr wrote: > > > > > > > On Sep 19, 10:20 pm, "Aaron S. Meurer" <asmeu...@gmail.com> wrote: > >> So given Chris's tip in issue 2058 (which flew over my head the first time > >> for some reason), I think I might have this figured out, except for one > >> thing. Given M(i, j, n), how to I get the third argument, n? I tried > >> M(i, j, n)[2] and M(i, j, n).args, but neither works. > >> > > > >>>> m = M(i,j,n) > >>>> m.args > > (M, i, j, n) > >>>> m.args[-1] > > n > -- You received this message because you are subscribed to the Google Groups "sympy" group. To post to this group, send email to sy...@googlegroups.com. To unsubscribe from this group, send email to sympy+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.
