On Apr 11, 2011, at 4:12 PM, Alexey U. Gudchenko wrote:

> 12.04.2011 01:56, Ronan Lamy пишет:
>> Le lundi 11 avril 2011 à 15:42 -0600, Aaron S. Meurer a écrit :
>>> On Apr 11, 2011, at 2:25 AM, smichr wrote:
>>> 
>>>> Should `Integral(x, (x, 1, 2)) == Integral(y, (y, 1, 2))` be True? If
>>>> so, smichr branch 2068b has a commit that makes this testing possible.
>>>> 
>>> This is a good question.  For one thing, == is not mathematical
>>> equality but exact equality, so there is no reason why it should have
>>> to be True.  So my initial response is that no, it should not.  
>>> 
>> I think it should. x and y are bound symbols that have no meaning
>> outside the integrals, so their identity should be completely
>> irrelevant. In fact, they should probably be replaced with dummies upon
>> instantiation of the Integral.
>> 
>> 
> 
> Mathematically equal. (especially when assumptions for symbols are equal
> too).
> 
> Another question what means "==" in SymPy: mathematical
> or not (pythonic?).
> 
> Aaron, what do you mean by "exact equality"?
> E.g Does the "Max(1, 2, x)" exact equal to the "Max(2, x)" or not?
> 
> 
> -- 
> Alexey U.

"Exact" meaning it checks if the objects are equal.  The usual example is that 
we have

>>> (x + 1)**2 == x**2 + 2*x + 1
False

I thought Max(1, 2, x) automatically reduced to Max(2, x).  In that case, then, 
obviously they would be equal with ==.  Also you would have Max(2, x) == Max(x, 
2) because it internally uses a data structure that does not care about order 
(set or frozenset). 

Whenever you see == in SymPy, it is specifically assuming this exact/object 
equality. 

Another thing to consider is:

In [190]: hash(Integral(x, (x, 0, 1)))
Out[190]: -9173880960074697984

In [191]: hash(Integral(y, (y, 0, 1)))
Out[191]: −299967655319032172

A == B should imply hash(A) == hash(B).

Aaron Meurer

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