Matthew, I agree that the x + 0.0 case should be treated the same as 1.0 * x. I think that the Reals/floats should never automatically (outside of possible internal routines) be converted to exact numbers. What happens if you're doing a machine precision calculation that occasionally reaches exactly 1.0 then gets converted to a slower exact arithmetic? I think that the mathematica convention (see below) is the correct one.
IPython console for SymPy 0.7.0-git (Python 2.7.1-64-bit) (ground types: python) In [1]: 1.0 * x Out[1]: 1.0⋅x In [2]: x + 0.0 Out[2]: x Mathematica 8.0 for Linux x86 (64-bit) In[1]:= 1.0 * x Out[1]= 1. x In[2]:= x + 0.0 Out[2]= 0. + x Simon -- You received this message because you are subscribed to the Google Groups "sympy" group. To view this discussion on the web visit https://groups.google.com/d/msg/sympy/-/qWaiHaxKvXkJ. To post to this group, send email to sympy@googlegroups.com. To unsubscribe from this group, send email to sympy+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.
