I just tried this in isympy and as long as you specify both real and
positive, it seems to work:
In [1]: r = Symbol('r', real=True, positive=True)
In [2]: sqrt(r*r)
Out[2]: r
In [3]: r = Symbol('r', real=True)
In [4]: sqrt(r*r)
Out[4]: │r│
On Thu, Aug 11, 2011 at 6:01 PM, Alan Bromborsky <abro...@verizon.net>wrote:
> I have a symbol r which should be assumed real and greater than zero. What
> I want is for sqrt(r*r) to evaluate to r. Can this be currently done in
> sympy. I am trying to clean up some old code that has a lot of hacks in it
> (curvilinear coordinates).
>
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