As I mentioned on the mailing list, this answer is valid. match() is
not guaranteed to give any particular answer when more than one is
valid, so you should always use the exclude keyword on Wild to make
the match unique.
Aaron Meurer
On Sun, Aug 21, 2011 at 4:59 PM, Sean Vig <sean.v....@gmail.com> wrote:
> I get that exact result, linux python 2.7.2.
> Sean
>
> On Sun, Aug 21, 2011 at 16:50, smichr <smi...@gmail.com> wrote:
>>
>> lazovich reported a failure of
>>
>> ```python
>> >>> a,b,c = map(Symbol, 'abc')
>> >>> x,y = map(Wild, 'xy')
>> >>> (a+b*I).match(x+y*I)
>> {x_: I*b, y_: -I*a}
>>
>> Could someone test this? It doesn't fail for me. w32 py27
>>
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