On Fri, Sep 16, 2011 at 3:19 AM, Hector <hector1...@gmail.com> wrote:
>
>
> On Fri, Sep 16, 2011 at 2:40 AM, Chris Smith <smi...@gmail.com> wrote:
>
>> instead of `a%p` write `a % p`. Also, since this will have to be
>> computed again later you might as well do both at the same time:
>>
>> a, r = divmod(a, p)
>
> if not r:
>> return 0
>> if is_quad_residue(a, p):
>> return 1
>> else:
>> return -1
>>
>
> for a, p = 5, 11; divmod(a, p) returns (0, 5) and we will be losing the
> value of a if a < p and hence with little modification -
>
A little more modification -
_, a = divmod(a, p)
if not a :
return 0
if is_quad_residue(a, p):
return 1
else:
return -1
>
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>
>
> --
> -Regards
> Hector
>
> Whenever you think you can or you can't, in either way you are right.
>
>
--
-Regards
Hector
Whenever you think you can or you can't, in either way you are right.
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