On Fri, Feb 10, 2012 at 12:17 PM, Laereom <jamesdbo...@gmail.com> wrote:
> Curioser and curioser.
>
> sym_x, sym_y = symbols('x,y')
> z = int(origin['z'])
> print origin
> print destination
>
> dest_x = int(destination['x'])
> dest_y = int(destination['y'])
> dest_z = int(destination['z'])
> equation = Eq( sqrt( (sym_x-dest_x)**2 + (sym_y-dest_y)**2 +
> (z-dest_z)**2 ) , 2 )
> #This should give us a line to walk towards.
> print solve( equation,sym_x)
>
> Output:
> {'y': 0, 'x': 0, 'z': 2}
> {'y': 3, 'x': 3, 'z': 3}
> []
So your equation is (I think) sqrt((x-3)**3+(y-3)**2+(2-3)**2) = 2
No problem is apparent. Make sure you are using the latest sympy;
upgrades have been made to solve.
>
>
> I noticed you're using vars, I'm guessing those are sympy related?
> Any reason I should worry about using hardcoded values like I am? I
> can't imagine why there would be, but I'm not exactly brimming with
> solutions. What I'm doing looks pretty similar to what you're doing.
>
>
> On Feb 9, 10:20 pm, Chris Smith <smi...@gmail.com> wrote:
>> Can you print your origin and destination variables? When using the
>> following, I don't have any problem:
>>
>> >>> var('a,b,c,x,y,z')
>> (a, b, c, x, y, z)
>> >>> eq=Eq(sqrt((x-a)**2+(1-b)**2+(z-c)**2), 2)
>> >>> solve(eq, x)
>>
>> [a - sqrt(-b**2 + 2*b - c**2 + 2*c*z - z**2 + 3), a + sqrt(-b**2 + 2*b -
>> c**2 +
>> 2*c*z - z**2 + 3)]
>
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