Does this help?
In [1]: expr = sin(x)**2
In [2]: p = Wild("p")
In [3]: expr.match(p**2)
Out[3]: {p: sin(x)}
On Mon, Mar 12, 2012 at 7:30 AM, Alan Bromborsky <abro...@verizon.net>wrote:
> On 03/12/2012 10:25 AM, Alan Bromborsky wrote:
>
>> Can assumptions handle the following case -
>>
>> I have the expression sin(th)**2 and know that sin(th)**2 > 0 and I want
>> sqrt( sin(th)**2) = sin(th).
>>
>> Failing the use of assumptions is there a way of telling if an
> expression is the square of another expression and what that expression is?
>
>
> --
> You received this message because you are subscribed to the Google Groups
> "sympy" group.
> To post to this group, send email to sympy@googlegroups.com.
> To unsubscribe from this group, send email to sympy+unsubscribe@**
> googlegroups.com <sympy%2bunsubscr...@googlegroups.com>.
> For more options, visit this group at http://groups.google.com/**
> group/sympy?hl=en <http://groups.google.com/group/sympy?hl=en>.
>
>
--
You received this message because you are subscribed to the Google Groups
"sympy" group.
To post to this group, send email to sympy@googlegroups.com.
To unsubscribe from this group, send email to
sympy+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/sympy?hl=en.
