Again, this is not what I get in the current master branch:
In [1]: (sin(x)/x**10).series(x,0,10)
Out[1]:
3 5
1 1 1 1 1 x x x
── - ──── + ────── - ─────── + ──────── - ──────── + ────────── - ────────────
9 7 5 3 362880⋅x 39916800 6227020800 130767436800
x 6⋅x 120⋅x 5040⋅x
7 9
x x ⎛ 10⎞
─ + ─────────────── - ────────────────── + O⎝x ⎠
0 355687428096000 121645100408832000
It works as expected. Can you check which version of sympy you are
actually using? Is it the master branch or a released version?
On 14 March 2012 16:32, Rhythm Gupta <rhythm.gupt...@gmail.com> wrote:
> I think Yes.
>
>
> On Wed, Mar 14, 2012 at 8:57 PM, Gaurav Sathe <gaurav.sath...@gmail.com>
> wrote:
>>
>> Thnx... I was thinking of the same logic which u have said... but then how
>> do we explain the below series expansion:
>>
>> >>> (sin(x)/x**10).series(x,0,10)
>> 1 1 1 1 1
>> ──────── + ── - ──── + ────── - ─────── + O(1)
>> 362880⋅x 9 7 5 3
>> x 6⋅x 120⋅x 5040⋅x
>>
>>
>> Do we say that it is like dividing each term of the sin(x) series by x**10
>> ?
>>
>> -Gaurav
>>
>>
>>
>> On Wed, Mar 14, 2012 at 7:44 PM, Sai Nikhil <tsnleg...@gmail.com> wrote:
>>>
>>> parameter 'n' was written to imply last exponent of 'x' in the expansion,
>>> I guess
>>>
>>> but, in second case, exp(x**2) = exp(v), where v = x**2 and so, exp(v) is
>>> calculated till, v**9 and substituting, v=x**2, we are getting the above
>>> result.
>>>
>>> this is obviously supposed to be an issue, and if Mr.Aaron permits, I'll
>>> try to submit a suitable patch for this ...
>>>
>>>
>>> -thanks ,
>>> Sai Nikhil.T
>>>
>>>
>>> 1
>>>
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>>
>>
>>
>>
>> --
>> Gaurav Sathe
>> -Student at BITS Pilani - Goa Campus
>>
>>
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