I'm trying to wrap an expression into a lambda and notice that the dummy variable of the lambda doesn't match with the variable of the expression. Am I doing this right?
Here, the lambda's i is not the same as the i in the expression I send: >>> def f(fi): ... return lambda i: fi ... >>> f(i+1)(1) i + 1 Here I remap the expression's i to the lambda's i >>> def f(fi): ... return lambda i: fi.subs(fi.free_symbols.pop(), i) ... >>> f(i+1)(1) 2 /c -- You received this message because you are subscribed to the Google Groups "sympy" group. To view this discussion on the web visit https://groups.google.com/d/msg/sympy/-/GdT_8xFkBDUJ. To post to this group, send email to sympy@googlegroups.com. To unsubscribe from this group, send email to sympy+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.
