On Thu, Aug 30, 2012 at 5:19 PM, David Joyner <wdjoy...@gmail.com> wrote:
> I guess the bottom line is I'm wondering how to enter the generators
> of the Rubik's cube group, eg at

>>> from sympy.combinatorics.generators import rubik_cube_generators
>>> gens = rubik_cube_generators()

A single one might be entered in cycle notation as:

Permutation([(0, 2, 7, 5), (1, 4, 6, 3), (8, 32, 24, 16), (9, 33, 25,
17), (10, 34, 26, 18)])

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